JS gets the position of the nth occurrence of a specified string in a string

Learn about similar methods for getting character positions:

charAt() Gets the character at the specified position in the string

Usage: strObj is a string object, index is the specified position (the position starts at 0)

strObj.charAt(index)

Usage: stringObject is a string object, searchvalue is the specified string value, fromindex (optional) specifies the position to start matching the string value. If not, it means starting from position 0.

stringObject.indexOf(searchvalue,fromindex)

For example:

var str = 'helloworld';
var num = str.indexOf('o'); // returns 4

Main topic

Get the position of the nth occurrence of a string value in the specified string

Like the example above, helloword, I want to get the position where the second o appears

js code: parameter (string, string value to be searched, the string value to be searched

function find(str,cha,num){
 var x=str.indexOf(cha);
 for(var i=0;i<num;i++){
  x=str.indexOf(cha,x+1);
 }
 return x;
 }

Quote the method:

ar str="Hello World!"
document.write(find(str,'o',1));//Return 7

The basic usage is like this. For a string with many identical characters, just replace the corresponding 2 with the n value you want to find.

For example: Get the position of the nth '/' in the current page URL

Call the above method directly

ar str=document.URL; //Get the complete path information of the current page document.write(find(str,'/',n));

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