MYSQL implements ranking and querying specified user ranking function (parallel ranking function) example code

MYSQL implements ranking and querying specified user ranking function (parallel ranking function) example code

Preface

This article mainly introduces the relevant content about MYSQL to realize ranking and query the specified user ranking function (parallel ranking function), and shares it for your reference and learning. Let's take a look at the detailed introduction.

Table structure:

CREATE TABLE test.testsort (
 
id int(11) NOT NULL AUTO_INCREMENT,
 
uid int(11) DEFAULT 0 COMMENT 'user id',
 
score decimal(10, 2) DEFAULT 0.00 COMMENT 'score',
 
PRIMARY KEY (id)
 
)
 
ENGINE = INNODB
 
AUTO_INCREMENT = 1
 
CHARACTER SET utf8
 
COLLATE utf8_general_ci
 
COMMENT = 'Test sorting'
 
ROW_FORMAT = DYNAMIC;

Idea: You can sort first and then number the results; you can also query the results first and then sort and number them.

illustrate:

@rownum := @rownum + 1 In this sentence, := is used for assignment. This means that @rownum + 1 is executed first, and then the value is assigned to @rownum.

(SELECT @rownum := 0) r This sentence means setting the initial value of the rownum field to 0, that is, the numbering starts from 1.

Achieve ranking:

Method 1:

SELECT t.*, @rownum := @rownum + 1 AS rownum
 
FROM (SELECT @rownum := 0) r, (SELECT * FROM testsort ORDER BY score DESC) AS t;

Method 2:

SELECT t.*, @rownum := @rownum + 1 AS rownum
 
FROM (SELECT @rownum := 0) r, testsort AS t
 
ORDER BY t.score DESC;

result:

View the ranking of a specified user:

Method 1:

SELECT b.* FROM
 
(
 
SELECT t.*, @rownum := @rownum + 1 AS rownum
 
FROM (SELECT @rownum := 0) r,
 
(SELECT * FROM testsort ORDER BY score DESC) AS t
 
) AS b WHERE b.uid = 222;

Method 2:

SELECT b.* from
 
(
 
SELECT t.*, @rownum := @rownum + 1 AS rownum
 
FROM (SELECT @rownum := 0) r, testsort AS t
 
ORDER BY t.score DESC
 
) as b where b.uid = 222;

result:

To achieve a tie ranking (same ranking for the same score):

SELECT
 
obj.uid,
 
obj.score,
 
CASE
 
WHEN @rowtotal = obj.score THEN
 
@rownum
 
WHEN @rowtotal := obj.score THEN
 
@rownum :=@rownum + 1
 
WHEN @rowtotal = 0 THEN
 
@rownum :=@rownum + 1
 
END AS rownum
 
FROM
 
(
 
SELECT
 
uid,
 
score
 
FROM
 
testsort
 
ORDER BY
 
score DESC
 
) AS obj,
 
(SELECT @rownum := 0 ,@rowtotal := NULL)

Query the ranking of a specified user:

SELECT total.* FROM
 
(SELECT
 
obj.uid,
 
obj.score,
 
CASE
 
WHEN @rowtotal = obj.score THEN
 
@rownum
 
WHEN @rowtotal := obj.score THEN
 
@rownum :=@rownum + 1
 
WHEN @rowtotal = 0 THEN
 
@rownum :=@rownum + 1
 
END AS rownum
 
FROM
 
(
 
SELECT
 
uid,
 
score
 
FROM
 
testsort
 
ORDER BY
 
score DESC
 
) AS obj,
 
(SELECT @rownum := 0 ,@rowtotal := NULL) r) AS total WHERE total.uid = 222;

Summarize

The above is the full content of this article. I hope that the content of this article will have certain reference learning value for your study or work. If you have any questions, you can leave a message to communicate. Thank you for your support for 123WORDPRESS.COM.

You may also be interested in:
  • Mysql sorting to get ranking example code
  • MySQL page access statistics and rankings
  • How to add ranking to custom field query results in MySQL
  • MySQL grouping to get the first few records in each group (ranking) with research on group by and order by
  • Summarize several common ranking problems in MySQL

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